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LenKa [72]
3 years ago
12

The measures of two supplementary angles are (3x + 9)° and (2x + 2)°. What is the measure of the smaller angle? A. 16.6° B. 69.6

° C. 22.6° D. 110.4°
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Supplementary angles sum to 180°, hence

3x + 9 + 2x + 2 = 180, that is

5x + 11 = 180 ( subtract 11 from both sides )

5x = 169 ( divide both sides by 5 )

x = 33.8

Hence the smaller angle has a measure of

2x + 2 = (2 × 33.8) + 2 = 67.6 + 2 = 69.6° → B

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Which is the domain of the function f(x)=-5/6[3/5]^*
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Answer:

5/63/5xxx equal to 0

Step-by-step explanation:

^^^^

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How many significant digits are in 1000.10?<br> c. 5<br> b. 3<br> d. 6<br> a. 2
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Passes through (1,12) and has a vertex (10,-4)
agasfer [191]

Answer: 16/81 (x-10)^2 -4

Step-by-step explanation:

To write a vertex equation with just a point and the vertex, you have to figure out the variables.

In vertex form, the equation is y = a (x-h)^2 + k

Your y is 12, x = 1, h = 10, and k = -4

Plug everything into equation

12 = a (1 - 10)^2 -4

12 = a (-9)^2 - 4

12 = 81a - 4

16 = 81a

16/81 = a

Now you know what the 'a' value is.

If you graph 16/81 (x-10)^2 -4 , you will get a point at (1,12) and a vertex of (10,-4)!

I hope this helps!

3 0
3 years ago
The length of the hypotenuse of the right triangle is 25 cm, the length of one of the legs is 10 cm. What is the length of the s
Anna007 [38]

Answer:

  21 cm

Step-by-step explanation:

Call the triangle ABC, with the right angle at B, the hypotenuse AC=25, and the given leg AB=10. The altitude to the hypotenuse can be BD. Since the "other leg" is BC, we believe the question is asking for the length of DC.

The right triangles formed by the altitude are all similar to the original. That means ...

  AD/AB = AB/AC . . . . . . ratio of short side to hypotenuse is a constant

Multiplying by AB and substituting the given numbers, we get ...

  AD = AB²/AC = 10²/25

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Then the segment DC is ...

  DC = AC -AD = 25 -4

  DC = 21 . . . . . centimeters

6 0
3 years ago
In how many ways can 7 persons be arranged in a line such that (a) two particular persons are never together.
ivanzaharov [21]

Answer:

3600 ways

Step-by-step explanation:

person A has 7 places to choose from :

→ He has 2 places ,one to the extreme left of the line ,the other to the extreme right of the line

If he chose one of those two ,person B will have 5 choices and the other 5 persons will have 5! Choices.

⇒ number of arrangements = 2×5×5! = 1 200

→ But Person A also , can choose one of the 5 places in between the two extremes .

If he chose one of those 5 ,person B will have 4 choices and the other 5 persons wil have 5! Choices.

⇒ number of arrangements = 5×4×5! = 2 400

In Total they can be arranged in :

1200 + 2400 = 3600 ways

3 0
2 years ago
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