Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is 
Generally the sample proportion is mathematically represented as

=> 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
Answer:
32 percent
Step-by-step explanation:
8,000×400÷100
Answer:
6b+3m
Step-by-step explanation:
I hope this helped.
Right off the bat we know that the y-intercept is going to be 5 because of the second co-ordinate.
Now for the slope, because the y co-ordinate doesn't change, it has no slope so the equation is simply: y=5
Hope this helps :)
Answer:
0.71
Step-by-step explanation:
The probability is a chance of an event happening. The probability of assured event is 100% or 1.
If there is no chance of an event happening the probability is zero (0).
The probability of snowing = 0.29
The probability of not snowing = 1 - 0.29
= 0.71