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just olya [345]
1 year ago
15

Given f(x)=4x - 7 8x +8 what is the end behavior of the function?

Mathematics
1 answer:
Vsevolod [243]1 year ago
5 0

The end behavior of the function f(x) describes the behavior of the function as x approaches the +∞  f(x) approaches to 1/2 and the x approaches the -∞  f(x) approaches to 1/2.

<h3>What is a function?</h3>

It is defined as a special type of relationship and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

\rm f(x) = \dfrac{4x-7}{8x+8}

For the end behavior:

As x → ∞  f(x) → 1/2

And x → -∞ f(x) → 1/2

Thus, the end behavior of the function f(x) describes the behavior of the function as x approaches the +∞  f(x) approaches to 1/2 and the x approaches the -∞  f(x) approaches to 1/2.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

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Solve for x in the function
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Answer:

4

Step-by-step explanation:

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3 years ago
C equals 2 pi r​; Cequals62.8 ​(Circumference of a​ circle)
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Answer:

about 10

Step-by-step explanation:

62.8 = 2 pi r/2

62.8/2 = pi r

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about 10 = r

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3 years ago
Solve the equation 0.4+0.5=-4.7-0.6z
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The measure of an exterior angle of a regular polygon is 24 find the measure if the interior angle then find the number of sides
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3 0
3 years ago
Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg
Fofino [41]

Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let <em>X</em> = number of college women on a diet.

The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.

The sample of women selected is, <em>n</em> = 267.

The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (\hat p) follows a Normal distribution.  

The mean of this distribution is:

\mu_{\hat p} = p = 0.70

The standard deviation of this distribution is: \sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028

Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z

**Use the <em>z</em>-table for the probability.

P(\hat p \geq 0.75)=1-P(Z

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

7 0
2 years ago
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