<h3>Remember these laws of integers:</h3>
- (+)(-)=(-)
- (-)(+)=(-)
- (-)(-)=(+)
- (+)(+)=(+)
Jfjdhdhfhdhdhfhfhffjfhfhfjfjfjfjfhfh
Answer:
14. x = 1
16. x = 4
18. x = 10
Step-by-step explanation:
14. We have ∠ HGF = ∠ HGP + ∠ PGF
Given, ∠ HGF = 177x + 1, ∠HGP = 1 + 99x and ∠ PGF = 78°
So, 177x + 1 = 1 + 99x + 78
⇒ 78x = 78
⇒ x = 1 (Answer)
16. We have ∠ BCD = ∠ BCK + ∠ KCD
Given that, ∠ BCK = 9x - 2, ∠ BCD = 174° and ∠ KCD = 34x + 4
So, 174 = 9x - 2 + 34x + 4 = 43 x + 2
⇒ 43x = 172
⇒ x = 4 (Answer)
18. We have ∠ IJK = ∠ IJR + ∠ RJK
Now, given that, ∠ RJK = 8x + 10, ∠ IJR = 5x +8 and ∠ IJK = 148°
So, 148 = 5x + 8 + 8x + 10 =13x + 18
⇒ 13x = 130
⇒ x = 10 (Answer)
12h + 20t = income
1.5(h + t) + 7h + 9t + 500 = expenses
12h + 20t - 1.5(h + t) + 7h + 9t + 500 > 0
Pull an x from the first two terms
x(x^3 + y^3) + (x^3 + y^3) Now x^3 + y^3 is a common factor.
(x^3 + y^3)*(x + 1) That should be far enough. It can be factored further by factoring (x^3 + y^3) but there is no point because you can't do anything after that. But in case you want to know how x^3 + y^3 factors
(x^3 + y^3) = (x + y)(x^2 - xy + y^2)
Which means you could write original polynomial as
(x + y)(x^2 - xy + y^2)(x + 1)
Part B
You factored the x out of xy^3 so that you would have a common factor (x^3 + y^3) to pull out as a common factor for the whole polynomial.