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serious [3.7K]
4 years ago
8

What is the domain of the function y = sqrt x + 4?

Mathematics
2 answers:
SOVA2 [1]4 years ago
8 0

Answer:

[-4,\infty)

Step-by-step explanation:

We are asked to find the domain of of the function y=\sqrt{x+4}.

We know that domain of a square root function is not defined for negative values, so we can set an inequality to find the domain of our given function as:

x+4\geq 0

x+4-4\geq 0-4

x\geq -4

Therefore, the domain of our given function is values of x greater than or equal to -4, that is [-4,\infty)

LekaFEV [45]4 years ago
5 0
The domain is the set of numbers that the x value can be.
In an equation like y=x the domain is all real numbers because x can be any number.

In the case of y =  \sqrt{x+4}, any x value that is less than or equal to -4 will not work because you would be taking the square root of a negative number, which doesn't work unless you're graphing on a complex plane, which I assume you aren't.

Thus, the domain is x \geq -4
I hope that helps!
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fomenos

Solve for x by completing the square:

2 x^10 + 3 x^9 - 5 x^8 - 9 x^7 - x^6 + 3 x^5 + 7 x^4 + 9 x^3 - x^2 - 6 x - 2 = 0

The left hand side factors into a product with five terms:

(x - 1)^2 (x + 1)^3 (2 x + 1) (x^2 - 2) (x^2 + 1) = 0

Split into five equations:

(x - 1)^2 = 0 or (x + 1)^3 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Take the square root of both sides:

x - 1 = 0 or (x + 1)^3 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Add 1 to both sides:

x = 1 or (x + 1)^3 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Taking cube roots gives 0 times the third roots of unity:

x = 1 or x + 1 = 0 or x + 1 = 0 or x + 1 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x + 1 = 0 or x + 1 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x + 1 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x = -1 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x = -1 or 2 x = -1 or x^2 - 2 = 0 or x^2 + 1 = 0

Divide both sides by 2:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x^2 - 2 = 0 or x^2 + 1 = 0

Add 2 to both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x^2 = 2 or x^2 + 1 = 0

Take the square root of both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x = sqrt(2) or x = -sqrt(2) or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x = sqrt(2) or x = -sqrt(2) or x^2 = -1

Take the square root of both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x = sqrt(2) or x = -sqrt(2) or x = i or x = -i

There are {2} duplicate solutions:

Answer: x = -1 or x = 1 or x = -1/2 or x = -i or x = i or x = sqrt(2) or x = -sqrt(2)

3 0
4 years ago
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zzz [600]

Answer:

1. Radius = 84.65 in

2. Circumference = 531.65 in

3. Diameter = 169.3 in

Step-by-step explanation:

1] In order to find the area of a circle, we use the formula

Area of a circle = πr²

Where r is the radius. So substitute the value of the area of the circle in the formula, to find the radius r.

22511 = π r²

r² = 22511 ÷ π

r = \sqrt{22511 / \pi }

<u>r = 84.65 in</u>

2] Now that we found the radius, we can easily find the circumference using the formula:

Circumference of a circle = 2πr

Substitute the value of r in the formula.

Circumference = 2 × π × 84.65

<u>Circumference = 531.87 in</u>

3] The diameter is twice the radius, so:

diameter = r × 2

diameter = 84.65 × 2

<u>diameter = 169.3 in</u>

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Step-by-step explanation:

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Please do take the time to read my explanation, it will only help you if you do...

Solution

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3 years ago
What is the surface area of the composite figure?
Bingel [31]
   
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A2 = 4 × 6 × 7 = 168 mm²

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A1 +  A2  + A3 = 36 + 168 + 48 = 252 mm²



7 0
3 years ago
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