250 percent of 8.2 is 20.5
The probability according to the given scenario is:
(a) <em>0.0395</em>
(b) <em>0.95</em>
(c) <em>0.076</em>
The given values are:
(a)
The probability that the b/w has tuberculosis as well as having (+) test will be:
→ 
By substituting the values, we get
→ 
→ 
(b)
The probability that a person does not have tuberculosis will be:
→ 
→ 
→ 
(c)
The person does not have tuberculosis as well as have a (+) test, the probability will be:
→ 
→ 
→ 
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.6 divided by 10 is .06 so .6 is 10 times more than .06. Hope this helps!
Answer:
Step-by-step explanation:
40(12/100)
480/100
$4.80
The answer is the first choice.
P(both even) = (4P1)(3P1) / 9P2