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Lelechka [254]
3 years ago
14

Solve for all complex roots (2x^10)+(3x^9)-(5x^8)-(9x^7)-(x^6)+(3x^5)+(7x^4)+(9x^3)-(x^2)-(6x)-2

Mathematics
2 answers:
Andrews [41]3 years ago
6 0

complex roots involve square roots of negative numbers

when writing complex roots, we use i where i=√-1


in your question, technically, we can't solve for x since it isn't equal to anything

if we assume that it's equal to 0, then

2x^{10}+3x^9-5x^8-9x^7-x^6+3x^5+7x^4+9x^3-x^2-6x-2=0

if we factor it using a factoring aid (because that's hard to factor) we get

(x-1)^2(x+1)^3(2x+1)(x^2-2)(x^2+1)=0

set each to 0


(x-1)²=0

x-1=0

x=1, not comlex


(x+1)³=0

x+1=0

x=-1, not a comlex root


(2x+1)=0

2x+1=0

2x=-1

x=-1/2, not a complex root


x²-2=0

x²=2

x=\pm \sqrt{2}, not a complex root


x²+1=0

x²=-1

x=\pm \sqrt{-1}

x=\pm i are complex roots




the 2 complex roots are i and -i where i=√-1

fomenos3 years ago
3 0

Solve for x by completing the square:

2 x^10 + 3 x^9 - 5 x^8 - 9 x^7 - x^6 + 3 x^5 + 7 x^4 + 9 x^3 - x^2 - 6 x - 2 = 0

The left hand side factors into a product with five terms:

(x - 1)^2 (x + 1)^3 (2 x + 1) (x^2 - 2) (x^2 + 1) = 0

Split into five equations:

(x - 1)^2 = 0 or (x + 1)^3 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Take the square root of both sides:

x - 1 = 0 or (x + 1)^3 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Add 1 to both sides:

x = 1 or (x + 1)^3 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Taking cube roots gives 0 times the third roots of unity:

x = 1 or x + 1 = 0 or x + 1 = 0 or x + 1 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x + 1 = 0 or x + 1 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x + 1 = 0 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x = -1 or 2 x + 1 = 0 or x^2 - 2 = 0 or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x = -1 or 2 x = -1 or x^2 - 2 = 0 or x^2 + 1 = 0

Divide both sides by 2:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x^2 - 2 = 0 or x^2 + 1 = 0

Add 2 to both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x^2 = 2 or x^2 + 1 = 0

Take the square root of both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x = sqrt(2) or x = -sqrt(2) or x^2 + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x = sqrt(2) or x = -sqrt(2) or x^2 = -1

Take the square root of both sides:

x = 1 or x = -1 or x = -1 or x = -1 or x = -1/2 or x = sqrt(2) or x = -sqrt(2) or x = i or x = -i

There are {2} duplicate solutions:

Answer: x = -1 or x = 1 or x = -1/2 or x = -i or x = i or x = sqrt(2) or x = -sqrt(2)

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The approximate length of side AB is 14.0. The correct option is B. 14.0 units

<h3>Law of sines </h3>

From the question, we are to determine the measure of side AB

First, we will determine the measure of angle A

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A + 65° + 35° = 180°

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2 years ago
Can someone help me please
Schach [20]

Answer:

Step-by-step explanation:

The system of equations is expressed as

y=-2x+7 - - - - - - - - 1

y=5x-7 - - - - - - - - -2

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