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Luba_88 [7]
3 years ago
14

How does f(t) change over the interval from t = 7 to t = 8?A f(t)​

Mathematics
1 answer:
denis23 [38]3 years ago
5 0

Answer:

you have you have and equation and then plug 7,8 into t and you get your awnser

Step-by-step explanation:

get your equationn by Reding the graph or table then to y2 minus y1 over x2 minus x1 and then look at the graph for the y-int and but then , in to t

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son4ous [18]

Answer:

37/200

Step-by-step explanation:

Event/Sample Space = .185 = 18.5%

7 0
3 years ago
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√ 19 + 6^2 ÷ 7.2^2 I need help ASAP
kumpel [21]

Answer:

0.143059384

Step-by-step explanation:

=> \frac{\sqrt{19+6^2} }{7.2^2}

=> \frac{\sqrt{19+36} }{51.84}

=> \frac{\sqrt{55} }{51.84}

=> \frac{7.416}{51.84}

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3 years ago
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a)A fruitseller bought 50kg of the fruits. He sold 30kg of fruits for the cost price of 35kg of fruits and he sold the remaining
alex41 [277]
<h2><u>Question</u><u>:</u><u>-</u></h2>

A fruitseller bought 50kg of the fruits. He sold 30kg of fruits for the cost price of 35kg of fruits and he sold the remaining quantity for the cost Price of 18kg of fruits. calculate his profit or loss percent in the total transaction.

<h2><u>Answer</u><u>:</u><u>-</u></h2>

let the cost price be 50x

→he sells 30kg of fruits on it's CP of 35 kg

→CP of 30kg fruits = 30x

→SP of 35kg fruits = 35x

→remaing fruits are 20kg

→he sells 20kg of fruits on CP of 16kg

→CP of 20kg fruits = 20x

→SP of 20kg fruits = 16x

→total CP is = 50x

→total SP is = (35 + 16) = 51x

→SP > CP (it means profit)

→profit = SP-CP

→ 51-50

→ 1

<h2 /><h2><u>Now,</u></h2>

→ Profit% = gain/CP × 100

→ Profit% = 1/50 × 100

→ 2%

Hence the fruit seller had a profit% of 2%.

7 0
2 years ago
Find the extreme values of f(x y)=xy subject to the constraint x^2 + y^2 -4 = 0
KATRIN_1 [288]
Via Lagrange multipliers:

L(x,y,\lambda)=xy+\lambda(x^2+y^2-4)

L_x=y+2\lambda x=0
L_y=x+2\lambda y=0
L_\lambda=x^2+y^2-4=0

yL_x=y^2+2\lambda xy=0
xL_y=x^2+2\lambda xy=0
\implies yL_x-xL_y=y^2-x^2=0\implies y^2=x^2
\implies x^2+y^2=4=2x^2\implies x^2=2\implies x=\pm\sqrt2\implies y=\pm\sqrt2

So we have four critical points to consider, (\sqrt2,\sqrt2),(-\sqrt2,\sqrt2),(\sqrt2,-\sqrt2),(-\sqrt2,-\sqrt2). If both coordinates are positive or both are negative, we get a maximum value of (\pm\sqrt2)^2=2; otherwise, we get a minimum of (-\sqrt2)(\sqrt2)=-2.
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3 years ago
A parallelogram in a circumscribed circle must be a
Aleonysh [2.5K]
Hi!

//gm circumscribed by a circle must be a cyclic quadrilateral.
6 0
3 years ago
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