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d1i1m1o1n [39]
3 years ago
5

An investigative question in your employee satisfaction study seeks to assess employee ""job involvement."" Create a measurement

question that uses the following scales: a) A graphic rating scale. b) A multiple rating list.
Mathematics
1 answer:
dexar [7]3 years ago
6 0

Answer:

A) A graphic rating scale- a scale where the participant places his or her response along a line or continuum; the score or measurement is its distance in millimeters from either endpoint.

B) A multiple rating list- a single interval or ordinal numerical scale where raters respond to a series of objects; results facilitate visualization.I will recommend a multiple rating list, because it is an easier process to conduct in a employee environment.  

Step-by-step explanation:

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. A firm produces a commodity and receives $100 for each unit sold. The cost of producing and selling x units is 20x + 0.25x 2 d
kirza4 [7]
So for each unit they get $100, so if they sell "x" units, they intake 100x, that's just the gross income, and therefore the Revenue.

Now, they have a cost of 20x + 0.25x² if they "x" units, now, bearing in mind that if you pluck out the costs out of the incoming revenue, what's leftover, is a surplus amount, namely the Profit.  Therefore, profit p(x) = revenue - costs, or  100x - (20x + 0.25x²), which is p(x) = -0.25x² +80x.

a)
now, what's the highest profit they can make?  check the picture below.

\bf p(x)=-0.25x^2+80x\\\\
-------------------------------\\\\
\textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lcclll}
p(x) = &{{ -0.25}}x^2&{{ +80}}x&{{ +0}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{80}{-0.50}~,~0-\cfrac{80^2}{-1} \right)\implies \left( \stackrel{\textit{quantity}}{160}~,~\stackrel{\textit{profit value}}{6400}  \right)

b)

well, if a tax is imposed on them, and say, they take it out of the revenue, then their new revenue is not 100x, is 90x, thus   \bf p(x)=-0.25x^2+70x

and you can use the same formula as above to get the x-coordinate for that vertex.

\bf p(x)=-0.25x^2+70x\\\\
-------------------------------\\\\
\textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lcclll}
p(x) = &{{ -0.25}}x^2&{{ +70}}x&{{ +0}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{70}{-0.50}~,~0-\cfrac{70^2}{-1} \right)

7 0
3 years ago
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UNO [17]

Answer:

c. 0<b<1

Step-by-step explanation:

F(x) = logb x

When b is less than 1 see attached graph

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