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sasho [114]
3 years ago
13

Equation 2x²-5x+1 has roots alpha and beta. Form quadratic equation with roots (alpha² + 1/alpha²) and (beta²+1/beta²)​

Mathematics
1 answer:
Dominik [7]3 years ago
8 0

Step-by-step explanation:

please see in the picture below.All step by step procedure

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IRINA_888 [86]

Answer:

3x^{3} (1+2x+3x^{3} )

Step-by-step explanation:

If you reverse the distributive property you would get something like this. You can double check if you want.

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3 years ago
For the rational function f(x)=5−xx2+5x+6, find the points on the graph at the function value f(x)=3.
Anit [1.1K]

Given:

The rational function is:

f(x)=\dfrac{5-x}{x^2+5x+6}

To find:

The points on the graph at the function value f(x)=3.

Solution:

We have,

f(x)=\dfrac{5-x}{x^2+5x+6}

Substituting f(x)=3, we get

3=\dfrac{5-x}{x^2+5x+6}

3(x^2+5x+6)=5-x

3x^2+15x+18=5-x

Moving all the terms on one side, we get

3x^2+15x+18-5+x=0

3x^2+16x+13=0

Splitting the middle term, we get

3x^2+3x+13x+13=0

3x(x+1)+13(x+1)=0

(3x+13)(x+1)=0

Using zero product property, we get

(3x+13)=0\text{ or }(x+1)=0

x=-\dfrac{13}{3}\text{ or }x=-1

Therefore, the required values are -\dfrac{13}{3},-1.

7 0
3 years ago
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