The correct answer I believe you are looking for is D. Elevator 1 is 13 feet above ground level, and Elevator 2 is 10 feet below ground level.
<u>Explaination:</u>
This is because if you start at (0, 0) Elevator one, will go up 13 on the y axis. Putting it at 13 feet above ground level. If you start Elevator 2 at ground level on (0, 0) and go down 10 it will make it -10 AKA 10 feet below ground level.
I hope this helps! :)
Answer:
When 6x - 4 = 8, x = 2.
Step-by-step explanation:
6x - 4 = 8
Add 4 to both sides.
6x = 12
Divide both sides by 6.
x = 2
Proof:
6x - 4 = 8
Substitute variable.
6(2) - 4 = 8
Multiply 6 and 2.
12 - 4 = 8
Subtract 4 from 12.
8 = 8
1). y-3=-2(x+4)
2) slope = 3/4
y+2=3/4(x+4)
y=3/4x +1
3x-4y=4
looks like only the last one
Answer:
![\large\boxed{A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right] }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-12%5C%5C6%26-8%5Cend%7Barray%7D%5Cright%5D%20%7D)
Step-by-step explanation:
![A=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] \cdot\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] =\left[\begin{array}{ccc}(-3)(-3)+(4)(-2)&(-3)(4)+(4)(0)\\(-2)(-3)+(0)(-2)&(-2)(4)+(0)(0)\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%264%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-3%29%28-3%29%2B%284%29%28-2%29%26%28-3%29%284%29%2B%284%29%280%29%5C%5C%28-2%29%28-3%29%2B%280%29%28-2%29%26%28-2%29%284%29%2B%280%29%280%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-12%5C%5C6%26-8%5Cend%7Barray%7D%5Cright%5D)
