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3 years ago

How many gallons each of 20% alcohol and 10% alcohol should be mixed to obtain 10gal of 11% alcohol?

Mathematics

1 answer:

Scilla [17]3 years ago

6 0

Answer:

20% alcohol = 1 gal

10% alcohol = 9 gal

Step-by-step explanation:

Let

x = 20% alcohol

y = 10% alcohol

x + y = 10 (1)

0.20x + 0.10y = 10*0.11

0.20x + 0.10y = 1.1 (2)

From (1)

x = 10 - y

Substitute x = 10 - y into (2)

0.20x + 0.10y = 1.1

0.20(10 - y) + 0.10y = 1.1

2 - 0.20y + 0.10y = 1.1

- 0.20y + 0.10y = 1.1 - 2

-0.10y = -0.9

y = -0.9/-0.10

y = 9 gal

substitute y = 9 into (1)

x + y = 10

x + 9 = 10

x = 10 - 9

x = 1 gal

20% alcohol = 1 gal

10% alcohol = 9 gal

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