Answer:
I think it would be 350$
Step-by-step explanation:
ok so you have to buy 10 shirts so you need to set up your problem which would be 10(12+8+15)
Then you would have to actually distribute which would give you 120+80+150
Finally you just add all of your numbers together which would be 350$
First, a bit of housekeeping:
<span>The meaning of four consecutive even numbers is 15. Wouldn't that be "mean," not meaning? Very different concepts!
The greatest of these numbers is _______ a^1
"a^1" means "a to the first power. There are no powers in this problem statement. Perhaps you meant just "a" or "a_1" or a(1).
The least of these numbers is ______a^2.
No powers in this problem statement. Perhaps you meant a_2 or a(2)
In this problem you have four numbers. All are even, and there's a spacing of 2 units between each pair of numbers (consecutive even).
The mean, or arithmetic average, of these numbers is (a+b+c+d) / 4, where a, b, c and d represent the four consecutive even numbers. Here this mean is 15. The mean is most likely positioned between b anc c.
So here's what we have: a+b+c+d
------------- = 15
4
This is equivalent to a+b+c+d = 60.
Since the numbers a, b, c and d are consecutive even integers, let's try this:
a + (a+2) + (a+4) + (a+6) = 60. Then 4a+2+4+6=60, or 4a = 48, or a=12.
Then a=12, b=14, c=16 and d=18. Note how (12+14+16+18) / 4 = 15, which is the given mean.
We could also type, "a(1)=12, a(2)=14, a(3) = 16, and a(4) = 18.
</span>
Answer:
0.05 im pretty sure to my calcutor
Step-by-step explanation:
Answer:
210
Step-by-step explanation:
you can do 200 + 10 = 210
You can also do 200 + 1 x10
Answers:
P ' (14, 6)
Q ' (12, 12)
R ' (18, 10)
========================================================
Explanation:
The point P(7,3) moves to P'(14, 6) after multiplying the x and y coordinates by 2.
7*2 = 14
3*2 = 6
Similarly, Q(6,6) moves to Q'(12,12) following that same rule. Lastly, the point R(9,5) moves to R'(18,10)
The points are twice as far away from the origin compared to their preimage counterparts. This in turn makes the side lengths of triangle P'Q'R' to be twice as long compared to the corresponding side lengths of triangle PQR. Both triangles are different sizes, but the same shape. That makes them similar triangles (but they aren't congruent).
