I got 16,000 tubes are sold in half a day because there are 720 minutes in 12 hours, and 43,200 seconds in 720 minutes then you divide by 2.7 and get 16,000

3 0

3 years ago

If a person puts 1 cent in a piggy bank on the first day, 2 cents on the second day, 3 cents on the third day, and so forth, how

cluponka [151]

This is an arithmetic sequence with the common difference being 1

and if u have 1 cent on day 1 and 2 cents on day 2....then on day 40, u would have 40 cents....but we need the sum of all the days..

the sum of an arithmetic sequence can be found using the formula :
sn = n(a1 + an) / 2
n = number of terms = 40
a1 = first term = 1
an = last term = 40

now we sub
s(40) = 40(1 + 40) / 2
s(40) = 40(41)/2
s(40) = 1640/2
s(40) = 820.....820 cents = $ 8.20 <== the sum

4 0

3 years ago

You and your friend are selling your old CDs. Your friend sells 14 the first day, and x the next day. You sell y the first day a

Deffense [45]

Answer: 30+x+y

Step-by-step explanation:

Commutative Property of Addition : a+b= b+a , where a and b are any arbitrary numbers.

Given : Number of CDs sold by friend on first day = 14

Number of CDs sold by friend on next day = x

Total CDs sold by friend = 14 +x

Number of CDs sold by you on first day = 16

Number of CDs sold by you on next day = y

Total CDs sold by you = 16+y

The expression that shows the total number of CDs sold both days =

Total CDs sold by friend + Total CDs sold by you

= 14 +x+ 16+y

= 14 +(x+ 16)+y

= 14 +(16+x)+y [By Commutative Property of Addition.]

= 14+16+x+y

= 30+x+y

Hence, the expression that shows the total number of CDs sold both days :

30+x+y

6 0

3 years ago