<span>5x²y + 2xy² + x²y
Combining like terms would be
6x²y + 2xy²
The two terms are now unique and cannot be combined any further. </span><span>
</span>
To make this a little clearer, let's give the pairs of inequalities the same denominator:
<span>Question 1:
</span>

?

First, apply the common denominator to the first fraction:

Do the same for the second:

Nest, compare the two fractions:

Therefore:

>

<span>
Question Two:</span>

?

Apply the common denominator to fraction one:

Fraction two:

Evaluate:

>

Therefore:
<span>
> 
</span>
Hope this helps!
Answer:
Step-by-step explanation:
Answer:
I would answer but I cannot see it sorry :D
Step-by-step explanation:
Total charges from bank A exists $15.
Total charges on Bank B spending exists $45.
<h3>How to estimate the
Total charges on bank B?</h3>
Given: Bank A charges a $15 monthly fee for a checking account and debit card, with unlimited transactions.
Shade 25 transactions.
Total charges from bank A = $15 monthly
Bank B charged a $35 monthly fee for a checking account and debit card, plus $ 0.70 for each transaction.
She made 25 transactions.
Total charges on bank B = $35 + (0.40)25
Total charges on bank B = $35+10
Total charges on bank B = $45
To learn more about Total charges on the bank refer to:
brainly.com/question/17226704
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