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alina1380 [7]
3 years ago
9

QUESTION 1: Which is the equation in slope-intercept form for the line that passes through (6, 16) and is perpendicular to 2x +

5y = 4?
A. y = - 2/5 x + 18
B. y = 2/5 x + 14
C. y = 5/2 x + 1
D. y = - 5/2 x + 31

QUESTION 2: What is the slope of a line parallel to the line whose equation is 3x + 6y = 9?

A. -1/2
B. 1/2
C. 2
D. 3

QUESTION 3: Which is the equation of a line perpendicular to the line with the equation 3x + 4y = 7?

A. 4x + 3y = 3
B. 4x - 3y = 5
C. 3x - 4y = 3
D. 3x + 4y =5

QUESTION 4: Which is the equation in slope-intercept form for the line that passes through (-2, 4) and is parallel to 2x + y = 4?

A. y = 1/2x + 5
B. y = -1/2x + 3
C. y = 2x + 8
D. y = -2x

QUESTION 5: Which best describes the relationship between the lines?

3x - y = -7

6x - 2y = 1

A. parallel
B. perpendicular
C. neither
D. same line
Mathematics
1 answer:
Lorico [155]3 years ago
4 0

question 1 is C) 5/2x+1

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Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
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Answer:

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Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

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Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

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Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

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(3.8*t) + (3*t) = 7.4 + 6

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                  t = 13.4/6.8

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Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

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