Answer:
Step-by-step explanation:
The terms of this sum make the arithmetic sequence.
The fomula of a sum of <em>n</em> terms of an arithmetic sequence:
![S_n=\dfrac{[2a_1+(n-1)d]\cdot n}{2}](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7B%5B2a_1%2B%28n-1%29d%5D%5Ccdot%20n%7D%7B2%7D)
We have
Substitute:
![S_{50}=\dfrac{[2\cdot2+(50-1)\cdot15]\cdot50}{2}=(4+49\cdot15)\cdot25=(4+735)\cdot25\\\\=739\cdot25=18,475](https://tex.z-dn.net/?f=S_%7B50%7D%3D%5Cdfrac%7B%5B2%5Ccdot2%2B%2850-1%29%5Ccdot15%5D%5Ccdot50%7D%7B2%7D%3D%284%2B49%5Ccdot15%29%5Ccdot25%3D%284%2B735%29%5Ccdot25%5C%5C%5C%5C%3D739%5Ccdot25%3D18%2C475)
Answer: h(3)= -4 h(-3)=-16
Step-by-step explanation:
Plug in 3 and -3 for x and solve
h(3)= 2(3)-10
h(-3)= 2(-3)-10
Answer:
<u>1/20 of the patrons at Joe's restaurant are expected to be male and out of town.</u>
Step-by-step explanation:
1. Let's review all the information provided for solving this question:
Proportion of patrons that are male at Joe's restaurant = 1/4
Proportion of patrons that are from out of town at Joe's restaurant = 1/5
2. What proportion would you expect to be male and out of town?
For finding the proportion of the patrons, that would be male and that would be from out of town, we do this calculation:
Proportion of patrons that are male at Joe's restaurant * Proportion of patrons that are from out of town at Joe's restaurant
<u>1/4 * 1/5 = 1/20 </u>
<u>It means that 1/20 of the patrons at Joe's restaurant are expected to be male and out of town.</u>
Answer:
V = 301 ft^3
Step-by-step explanation:
The volume of a cone is given by
V =1/3 pi r^2 h
We know pi = 3.14 r =6 and
We need to determine h
We can find h from the Pythagorean theorem where 6 is a leg and 10 is the hypotenuse
h^2 +6^2 = 10^2
h^2 +36 = 100
h^2 = 64
Taking the square root of each side
h = 8
V =1/3 pi r^2 h
V = 1/3 (3.14) (6)^2 * 8
V = 301.44 ft^3
Rounding to the nearest cubic foot
V = 301 ft^3
Replace every x you see in the function with 1 and simplify.
Let x be 1.
f(1) = 4(1)^2 -(1) + 3
f(1) = 4(1) - 1 + 3
f(1) = 4 - 1 + 3
f(1) = 3 + 3
f(1) = 6
Done!
