(20 POINTS AND BRAINLIEST ANSWER!!!)

Mathematics

1 answer:

alisha [4.7K]3 years ago

8 0

PICTURE1: They are both 45

PICTURE2: 810

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Please help I don’t understand.

Lina20 [59]

You can work out c first. That's probably the key to the whole problem.
The adjacent side to a 60o angle is 1/2 the hypotenuse
The hypotenuse in this case = 4 Sqrt(3)
Then c = 1/2 (4 sqrt(3))
c = 2 sqrt(3) That means d is not true.

Next work out a.
a is in the same triangle as c and the hypotenuse.
a^2 + c^2 = hypotenuse^2
a = ??
c = 2 sqrt(3)
h = 4 sqrt(3)
a^2 + (2 sqrt(3))^2 = (4 sqrt(3))^2
(sqrt(3))^2 = 3
a^2 + 4 * 3 = 16 * 3
a^2 + 12 = 48
a^2 = 48 - 12
a^2 = 36
a = 6

Now we need to work out d
The side opposite and the side adjacent are equal when opposite a 45o angle in a right angle triangle
d = 6

The last thing to work out is be
a = 6
d = 6
c = ???

a^2 + d^2 = c^2
6^2 + 6^2 = c^2
c^2 = 72
c = sqrt(72)
c = sqrt(6*6*2)
c = 6 sqrt(2)

The answer should be B??? Check this out.

4 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! THIS IS THE LAST DAY TO COMPLETE THIS ASSIGNMENT AND I DESPERATELY NEED TO FI

Gekata [30.6K]

<h3>A television with a 5:4 screen shows an image with a ratio of 20:12 which creates a letter boxed image. What percent of the screen's area is occupied by the image?</h3>

Answer: d. 75% of the screen is occupied by the image

Step-by-step explanation:

First we have to find a relation between image area and screen area.

Image area is the product of image dimensions.

Screen area is the product of screen dimensions.

We have to divide the major image dimension between the major screen dimension

Major image dim/Major screen dim = 20/5 = 4

Now we have to multiply this relation by the minor screen dimension

Minor screen dim x 4 = 4 x 4 = 16

Then we have found 5/4 = 20/16

Now we can calculate what percent of the screen area is occupied by the image area.

Major image dim x minor image dim/Major screen dim x minor screen dim