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3 years ago

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Given a mean of 52.3 and a standard deviation of 1.8, what is the z-score of the value 51.8 rounded to the nearest tenth?

1 answer:

postnew [5]3 years ago

8 0

The z-score of a certain data point in the given statistical data is calculated through the equation,
z-score = (x - m) / sd
where x is the data point, m is the mean and sd is the standard deviation.
Substituting the known values,
z-score = (51.8 - 52.3) / 1.8
z-score = -0.277
Rounding the answer to the nearest tenth will give an answer of -0.3.

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The expression is given as:

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