Answer:
the y-intercept is where the line on the graph intercepts with the y-axis. in this case the y-intercept would be at (0,0)
First, find any zero of the polynomial. Since you didn't ask for work, I'll assume it's okay if I use my calculator. Your given polynomial has only one real root which is x=-4.
Now we use the rule that x-a divides the polynomial where a is a zero of said polynomial.
So x+4 divides 2x^3+2x^2-19x+20.
<span>(2x^3+2x^2-19x+20) / (x+4 equals 2x^2-6x+5).
If we factor out a two, we can use the quadratic formula.
2(x^2-3x+2.5) so we have x = (-(-3)+/-(9-4*1*2.5)^(1/2))/2*1)=(3+i)... or (3-i)/2 Where i is the square root of negative one. final answer:
2x^3+2x^2-19x+20=0
then x=-4, (3+i)/2, or (3-i)/2
</span>we have two imaginary number.
I hope it helped you
Answer:
y=x+2
y=x+4
slope intercept form is y=mx+b
I got E and F. A would be correct as is I think, B is 9^2x, C, correct as is, D, is 9 ^2x, and E and F is 9^x
Is 76.63 because:
If it is 5 or above, you give it one more point .
If it is 4 or below, you let it stay still.
