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Leya [2.2K]
3 years ago
13

What’s the correct answer

Mathematics
2 answers:
QveST [7]3 years ago
7 0

Answer:

79°

Step-by-step explanation:

Using the cosine rule in ΔABC

cosA = \frac{b^2+c^2-a^2}{2bc}

with a = 14, b = 11, c = 11, then

cosA = \frac{11^2+11^2-14^2}{2(11)(11)} = \frac{46}{242}

A = cos^{-1}(\frac{46}{242}) ≈ 79°

DENIUS [597]3 years ago
7 0

Answer:

(A) 79°

Step-by-step explanation:

We can use law of cosine.

c²=a²+b²-2ab*cos(α)

14²=11²+11²-2*11*11*cos(A)

14²=2*11²-2*11²cos(A)

14²-2*11²=-2*11²cos(A)

-46= - 2*(121)*cos(A)

cos(A)= 46/242

arccos(46/242)=79°

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X and y vary inversely and x=50 when y=5 find y when x=10 what is k?
Kisachek [45]

Answer:

Part A)

1)  k=250

2) y=25

Part B)

1)  k=7

2) y=84

Step-by-step explanation:

Part 1) x and y vary inversely and x=50 when y=5 find y when x=10 what is k?

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form y*x=k or y=k/x

step 1

<u>Find the value of k</u>

x=50 when y=5

substitute the values

y*x=k ------> 5*50=k -----> k=250

The equation is equal to

y*x=250  or y=250/x

step 2

<u>Find y when x=10</u>

substitute the value of x in the equation and solve for y

y*(10)=250

y=250/10=25

Part B) x and y vary directly and x=6 when y=42 find k what is y when x=12

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx

step 1

<u>Find the value of k</u>

x=6 when y=42

substitute the values

y/x=k ------> 42/6=k -----> k=7

The equation is equal to

y/x=7  or  y=7x

step 2

<u>Find y when x=12</u>

substitute the value of x in the equation and solve for y

y=7(12)=84

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Step-by-step explanation:

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