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3 years ago

Why does it take 3 copies of 1/6 to show the same amount as 1 cooy of 1/2

Mathematics

1 answer:

aleksandrvk [35]3 years ago

4 0

Because 1/2 = 3/6
therefore you have to multiply 1/6 by 3 to achieve that.

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In a bag, Gary has 3 red marbles, 4 blue marbles, 7 yellow marbles, 5 green marbles, 6 purple marbles, and 8 clear marbles. What

miskamm [114]

Answer:

2220

Step-by-step explanation:

gcd of all numbers

3,4,7,5,6,8

2 = 3,2,7,5,3,4

2 = 3,1,7,6,3,2

2 = 3,1,7,5,3,1

3 = 1,1,7,5,1,1

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2 years ago

Write the equation in slope-intercept form that contains the following point and is perpendicular to the given line

Len [333]

Answer:

y = 1/4 x -3

Step-by-step explanation:

y = -4x + 3;

the slope of this equation is -4

we want the slope perpendicular to this

take the negative reciprocal

- (-1/4) = 1/4

so the slope of our line will be 1/4

we have the slope and a point so we can use point slope form

y-y1 = m (x-x1)

y--2 = 1/4(x-4)

y+2 = 1/4 (x-4)

we need to change it to slope intercept form (y=mx+b)

distribute

y+2 = 1/4 x -1/4*4

y+2 = 1/4x -1

subtract 2 from each side

y +2-2 = 1/4 x -1-2

y = 1/4 x -3

the slope is 1/4 and the y intercept is -3

8 0

3 years ago

The baseball diamond at a playground is a square with sides that measure 90 feet, About how long would a straight line be from h

Nina [5.8K]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

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2 years ago

Which of the following expressions is equivalent to 1/3^-3?

sweet [91]

I believe B . Because it seems equivalent

8 0

3 years ago