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balu736 [363]
4 years ago
15

9.

Mathematics
2 answers:
frosja888 [35]4 years ago
7 0

Answer:

B) x = 2, y = 3, z = 5

Step-by-step explanation:

3x −2y + 4z = 20

3(2) - 2(3) + 4(5) = 20

20 = 20

−x + 5y +12z = 73

-2 + 5(3) + 12(5) = 73

73 = 73

x + 3y −2z = 1

2 + 3(3) - 2(5) = 1

1 = 1

Novay_Z [31]4 years ago
4 0

Answer:

B) x = 2, y = 3 and z = 5.

Step-by-step explanation:

3x −2y + 4z = 20    .....A

-x + 5y+ 12z = 73     .....B

x + 3y −2z = 1   ......C

Adding B and C:

8y + 10z = 74 .... E

Multiply equation B by -3:

-3x - 9y + 6z = -3

Add this equation to A:

-11y + 10z = 17

Subtract this equation fro E:

19y = 57

y = 3.

Substitute y = 3 in equation E:

8*3 + 10z = 74

10z = 50

z = 5.

Finally substitute  y = 3 and z = 5 into equation C:

x + 3(3) - 2(5) = 1

x + 9 - 10 = 1

x = 1 + 1

x = 2.

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