Answer:
The correct answer is the formation of pyruvate from glucose willl be energetically less favorable.
Explanation:
According to the question matunt yeast has a shorter glycolytic pathay catalysing a follwing reaction
Glyceraldehyde-3-phosphate+H2O+NAD+ = 3-phosphoglycerate
So in the mutatant the formation of 1,3- bisphosphoglycerate is not occurring.The glyceraldehyde-3-phosphate is directly converted into 3-phosphoglycerate.
As a result the substrate level phosphorylation step that deals with formation of 3-phosphoglycerate from 1,3 bisphosphoglycerate is not occurring.
From this point of view it can be said that less energy will be formed in the mutant during glycolysis than that of normal one.
So the formation of pyruvate from glucose will be energetically less favorable.
The enzyme that breaks down H2O2 is called catalase.
