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ra1l [238]
3 years ago
7

How do you do scientific notation

Mathematics
2 answers:
borishaifa [10]3 years ago
5 0

Answer:

In scientific notation, you move the decimal place until you have a number between 1 and 10. Then you add a power of ten that tells how many places you moved the decimal. In scientific notation, 2,890,000,000 becomes 2.89 x 109.

Step-by-step explanation:

kari74 [83]3 years ago
3 0

Answer:

In scientific notation, you move the decimal place until you have a number between 1 and 10.

Step-by-step explanation:

boom

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:) help out luvs!Thanks baes
frozen [14]

Answer:

A = 3

B = 4

C = 6

D = 5

E = 2

F = 7

G = 1

Step-by-step explanation:

Hopes it helps!

5 0
3 years ago
PLEASE HELP ITS DUE IN 20 MINUTES
anastassius [24]

Answer:14

Step-by-step explanation: it's says x= the sign at the end meaning whatever x is it's greater than 2 and 14 is the only one greater than 2

8 0
3 years ago
Least common factor of 15 and 20
Colt1911 [192]

Answer:

60

Step-by-step explanation:

5 0
3 years ago
if event A has a 30% chance of occurring and event B has a 45% chance of occurring, what is the probability that event A or even
Marysya12 [62]
The answer is 75%. This is because the 'or' rule for probability, the one we use when trying to determine P(A) or P(B), is to add the two probabilities. This means that we just need to add 30% and 45%, which gives us 75%.
I hope this helps!
3 0
3 years ago
The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0
3 years ago
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