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Travka [436]
3 years ago
9

This screenshot is the question.

Mathematics
2 answers:
Simora [160]3 years ago
6 0

Answer: The rectangular prism has the greater volume because the cylinder fits within the rectangular prism with space to spare.

P.S. To the other answerer: Once you answer, the asker is no longer allowed to change the question.  Use the "ask for details" comment button next time please.

DIA [1.3K]3 years ago
3 0
We need to see the options under choose.
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Sam needs at least 78 credits to get his college degree. At the end of his third year, Sam has a total of 52 credits. Which ineq
Sergio039 [100]

Answer:

C + 52 ≥ 78

Step-by-step explanation:

Since Sam needs at least 78 credits to a college degree, the inequality is represented by a more than or equal to symbol (≥).

7 0
4 years ago
A local little league has a total of 85 players, of whom 40% are left-handed. How many left-handed players are there?
Mkey [24]

Answer:

34 players

Step-by-step explanation:

40.00%

=0.4

0.4*85

=34

3 0
3 years ago
Simplify the expression using the distributive property. –4(–3x + 11) 1. Distribute the –4 through the parentheses: -4(–3x) + (-
diamong [38]
Let’s start with -4(-3x + 11) so, -4•-3x is 12x,because multiplying 2 negatives creates a positive. As for -4•11, it is -44. So, it should be 12x + -44. I hope this helps!
8 0
4 years ago
Read 2 more answers
It cost $36.75 for 3 tickets to visit science center. How much dose it cost for 1
Simora [160]

Answer: 12.25 dollars

Step-by-step explanation:

7 0
3 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
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