Answer:
Distance swam by Sonya in 3 weeks = 19740 m
Step-by-step explanation:
To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks.
Number of days in 1 week = 7
Number of weeks she swam = 3
Total number of days she swam = 3 x 7 = 21 days
Distance swam per day = 0.94 km
Total distance swam = Total number of days she swam x Distance swam per day
Total distance swam = 21 x 0.94 = 19.74 km = 19.74 x 1000 m = 19740 m
Distance swam by Sonya in 3 weeks = 19740 m
Answer:
y = 6x² -13x -5
Step-by-step explanation:
(1,-12) (2,-7) (5,80)
y = ax² + bx + c
-12 = a*1² + b*1 + c = a+b+c (1)
-7 = 4a + 2b + c (2)
80 = 25a + 5b + c (3)
(2)-(1): 3a + b = 5 (4)
(3)-(2): 21a + 3b = 87 (5)
(4)*3: 9a + 3b = 15 (6)
(5)-(6): 12a = 72 a = 6
(4) b = -13
(2) c = -5
Answer:
y=4
Step-by-step explanation:
Read off the graph. The corresponding y-coordinate when the x-coordinate is 7 is 4.
It would be c plz mark me brainliest
