a generator needs a fixed amount of fuel to keep it running two hours a day. After running for 6 days, the generators fuel tank
1 answer:
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Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
Answer:
Step-by-step explanation:
» Collect second degree terms (x² coefficients) together and first degree terms (x coefficients) and constants