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snow_lady [41]
3 years ago
8

a generator needs a fixed amount of fuel to keep it running two hours a day. After running for 6 days, the generators fuel tank

was 2/3 full. After 11 more days, 3 1/2 liters of fuel was left in the tank. If the tank was originally full, how much fuel can the tank hold?
Mathematics
1 answer:
statuscvo [17]3 years ago
5 0
<h3>Answer:</h3>

63 liters

<h3>Explanation:</h3>

The amount of fuel used per day is ...

... (1 tank - 2/3 tank)/(6 days) = (1/3 tank)/(6 days) = (1/18) tank/day

Then the amount of fuel used after 6+11 = 17 days is

... (17 days)×(1/18 tank/day) = 17/18 tank

and the amount remaining is ...

... (1 tank -17/18 tank) = 1/18 tank = 3 1/2 liters

To find the tank size, we can multiply this result by 18:

... 1 tank = 18×(3 1/2 liters) = 63 liters

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makkiz [27]

Answer:

x= 95 duhhhhhhh lol jk but its 95

Step-by-step explanation:

6 0
3 years ago
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Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = 3 (*sqaure root sign*) t (20 − t), [0,
mafiozo [28]

9514 1404 393

Answer:

  • maximum: 15∛5 ≈ 25.6496392002
  • minimum: 0

Step-by-step explanation:

The minimum will be found at the ends of the interval, where f(t) = 0.

The maximum is found in the middle of the interval, where f'(t) = 0.

  f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)

This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...

  f(5) = (∛5)(20-5) = 15∛5

The absolute maximum on the interval is 15∛5 at t=5.

5 0
3 years ago
FOR AN EXAM DUE TODAY!!!<br><br> Simplify the polynomial.<br> 3x – 2x2 + 4 – x2 + x<br> +<br> -
Mashutka [201]

Answer:

{ \tt{ \blue{  - {3x}^{2} + 4x + 4 }}}

Step-by-step explanation:

{ \tt{3x -  {2x}^{2}  + 4 -  {x}^{2} + x }} \\

» Collect second degree terms (x² coefficients) together and first degree terms (x coefficients) and constants

= { \tt{( - 2 - 1) {x}^{2} + (3 + 1)x + 4 }} \\  = { \boxed{ \tt{ \:  -  {3x}^{2}  + 4x + 4}}}

7 0
3 years ago
When Mr. P. drinks an 8-ounce glass of cola, how many teaspoons of sugar is he consuming if one teaspoon of sugar provides 4 gra
natta225 [31]

The number of teaspoons of sugar that Mr. P. consumes is = 56.7 teaspoons.

<h3>Calculation of total sugar quantity</h3>

The total amount of cola taken is 8-ounce

To covert ounce to grams , the following is carried out;

1 ounce =28.35g

8 ounce = X

Xg = 8 × 28.35

X = 226.8g

But one teaspoon = 4 grams

X teaspoon = 226.8g

cross multiply to solve for x

X = 226.8g/ 4

X = 56.7 teaspoons

Therefore, the number of teaspoons of sugar that Mr. P. consumes is = 56.7 teaspoons.

Learn more about multiplication here:

brainly.com/question/10873737

4 0
2 years ago
Solve the equation <br> y-x=17<br> y=4x+2
gogolik [260]
Y-x =17
y = -x + 17

substitute this into the second equation

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3 = x
4 0
3 years ago
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