x^2 + y^2 + 2x - 6y + 1 = 0
x^2 +2x + 1 + y^2 - 6y = 0
x^2 + 2( x × 1) + 1^2 + y^2 - 2(y×3) + 3^2 -3^2 =0
(x+1)^2 + (y-3)^2 = 3^2
comparing with circle equation
(x-a)^2 + (y - b)^2 = r^2
where (a , b) is centre of circle.
so we get center of circle is
(-1, 3)
Answer:
c=80
Step-by-step explanation:
Based on my reading the critical damping occurs when the discriminant of the quadratic characteristic equation is 0.
So let's see that characteristic equation:
20r^2+cr+80=0
The discriminant can be found by calculating b^2-4aC of ar^2+br+C=0.
a=20
b=c
C=80
c^2-4(20)(80)
We want this to be 0.
c^2-4(20)(80)=0
Simplify:
c^2-6400=0
Add 6400 on both sides:
c^2=6400
Take square root of both sides:
c=80 or c=-80
Based on further reading damping equations in form
ay′′+by′+Cy=0
should have positive coefficients with b also having the possibility of being zero.
Answer:
Y=10x
Step-by-step explanation:
I hope this helped you
Answer:
Step-by-step explanation:
You need to set up a proportion
Let x = NK
7/13 = x/56 Notice that the longest side of the small trapezoid is the denominator of the fraction on the left. That means that the longest side of the large trapezoid must also be the denominator of that fraction on the right.
Cross multiply
13x = 7*56 Combine the right
13x = 392 Divide by 13
x = 392/13
x = 30.15
NK = 30.15
The ordered pair (-1,5) is a solution to the system because it makes both equations true.
1) x+y=4
2) x-y=-6
1) -1 + 5 = 4
5-1 = 4 you can switch the order to make it easier to understand
so
4 = 4
2) -1 - 5 = -6
-1 + -5 = -6 you can change the sign in the middle and make y -
so
-6 = -6
