Please help me!!! 30 points, will report for ridiculous responses.
1 answer:
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Answer:
y=-3x+5
Explanation:
Given a line L such that:
• L has y-intercept (0,5); and
,• L is perpendicular to the line with equation y=(1/3)x+1.
We want to find the equation of the line in the slope-intercept form.
The slope-intercept form of the equation of a straight line is given as:
Comparing the given line with the form above:
Next, we find the slope of the perpendicular line L.
• Two lines are perpendicular if the product of their slopes is -1.
Let the slope of L = m1.
Since L and y=(1/3)x+1 are perpendicular, therefore:
The y-intercept of L is at (0,5), therefore:
Substitute the slope, m=-3, and y-intercept, b=5 into the slope-intercept form.
The equation of line L is:
To get the result we have to transform given formula into y=ax+b form.
Lets do this
5x+3y=6 /-5x (subtract 5x both sides)
3y=-5x+6 /:3 (divide both sides by 3)
y=
In form y=ax+b we know that a is slope and b is y intersect. We can read from our transformed equation that slope a=
and its the result
Lets do this
5x+3y=6 /-5x (subtract 5x both sides)
3y=-5x+6 /:3 (divide both sides by 3)
y=
In form y=ax+b we know that a is slope and b is y intersect. We can read from our transformed equation that slope a=