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Nata [24]
4 years ago
8

Whar is 10.034 rounded to the nearest tenth​

Mathematics
1 answer:
VLD [36.1K]4 years ago
8 0

Answer: 10.0

Step-by-step explanation: In this problem, we are asked to round 10.034 to the nearest tenth. It's important to understand that the tenths place is 1 place to the right of the decimal point. So the digit in the rounding place is 0.

Next, look at the digit to the right of the rounding place which in this case is 3. Since the digit to the right of the rounding place, 3, is less than 5, we round down.

This means that the digit in the rounding place, 0, stays the same and we change all digits to the right of the rounding place to 0.

So 10.034 rounded to the nearest tenth is 10.000 or just 10<em>.</em>0 since we can drop zeroes at the end of a decimal.

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The area of the triangle is 72 square cm.

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A bank is investigating ways to entice customers to charge more on their credit cards. (Banks earn a fee from the merchant on ea
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Answer:

CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\

CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )

The correct answer choice is a. (62.2, 113.8)

Step-by-step explanation:

Of the 500 customers who were told the increase applied to charges above $1000 each month, the average increase in spending was $527 with a standard deviation of $225.

Sample size = n₁ = 500

Sample mean = x₁ = $527

Standard deviation = s₁ = $225

Of the 500 customers who were told the increase applied to charges above $2000 each month, the average increase in spending was $439 with a standard deviation of $189

Sample size = n₂ = 500

Sample mean = x₂ = $439

Standard deviation = s₂ = $189

We are asked to find the 95% confidence interval for the difference between two means.

The given group of answer choices are

a. (62.2, 113.8)

b. (86.2, 120.5)

c. (10.3, 23.8)

d. (55.6, 67.8)

The confidence interval for the difference between two means is given by

CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\

Where \bar{x_{1} } and \bar{x_{2} } are the given sample means and margin of error is given by

$ MoE = z_{\alpha/2} \cdot \sqrt{\frac{s_{1}^2}{n_1} + \frac{s_{2}^2}{n_2}} $

The z-score corresponding to 95% confidence level is given by

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

From the z-table at α = 0.025 the z-score is 1.96

$ MoE = 1.96 \cdot \sqrt{\frac{225^2}{500} + \frac{189^2}{500}} $

MoE = 1.96 \cdot 13.14

MoE = 25.75

Finally,

CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\

CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )

Therefore, the correct answer choice is a. (62.2, 113.8)

How to use z-table?

In the z-table find the probability of 0.025

Note down the value of that row, it would be 1.9.

Note down the value of that column, it would be 0.06.

Add the two numbers together.

The z-score is 1.9 + 0.06 = 1.96

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