Answer:
8 (2 g + 1) (4 g^2 - 2 g + 1)
Step-by-step explanation:
Factor the following:
64 g^3 + 8
Factor 8 out of 64 g^3 + 8:
8 (8 g^3 + 1)
8 g^3 + 1 = (2 g)^3 + 1^3:
8 (2 g)^3 + 1^3
Factor the sum of two cubes. (2 g)^3 + 1^3 = (2 g + 1) ((2 g)^2 - 2 g + 1^2):
8 (2 g + 1) ((2 g)^2 - 2 g + 1^2)
1^2 = 1:
8 (2 g + 1) ((2 g)^2 - 2 g + 1)
Multiply each exponent in 2 g by 2:
8 (2 g + 1) (4 g^2 - 2 g + 1)
2^2 = 4:
Answer: 8 (2 g + 1) (4 g^2 - 2 g + 1)