Formulas tab > in the Function Library group, click Lookup & Reference button, select VLOOKUP. Type A3 in the Lookup_value argument box. Type Abbreviation in the Table_array argument box. Type 2 in the Col_num argument box. Type False in the Rang_lookup box. Click OK, is this what you were looking for?
Answer:
See the step-by-step explanation
Step-by-step explanation:
Let c be any element of C. (I'm not sure wether you have to assume that C is non-empt or not)
C is a subset of B. That means that as c is in C, it is also in B. (
)
Now, B is a subset of A. It follows that as 
.
That means c is an element of A. The predicate Q is true for all elements of A, including c.
Because we let c be any element of C, we have proven that the predicate Q is true for all elements in C.
Answer:
D. 119
Step-by-step explanation:
To find the common difference, we take the second term and subtract the first term
2-(-7) = 9
We check by taking the third term and subtracting the second
11-2 = 9
The common difference is 9
The formula for an arithmetic sequence is
an = a1 +d(n-1)
where a1 is the first term, d is the common difference and n is the number of the term in the sequence
a1=-7, d=9 and we are looking for the 15th term so n=15
a15 = -7 +9(15-1)
a15 = -7+9(14)
=-7 +126
= 119
Answer:
151 mol Ne.
Step-by-step explanation:
I did work on Paper sorry if i can't type it, It'll mess it up.
Answer: 20%
Step-by-step explanation:
To find the total number of problems Emilia solved, we can first add 19 and 76 to get:
19 + 76 = 95
Next, to find how many problems Emilia got correct out of the total, we can use the number of problems correct (19) and divide it by the total number of problems (95) to get:
19 ÷ 95 = 0.2
Finally, to make 0.2 a percentage, we can multiply it by 100 to get:
0.2 X 100 = 20
Therefore, Emilia got 20% of the problems correct.
