Answer:
This means that f(x)→∞ as x→−∞ and f(x)→∞ as x→∞.
Step-by-step explanation:
Since the leading term of the polynomial (the term in a polynomial which contains the highest power of the variable) is x4, then the degree is 4, i.e. even, and the leading coefficient is 1, i.e. positive.
This means that f(x)→∞ as x→−∞ and f(x)→∞ as x→∞.
true or false? no question?
if so
Faults because 50% is based on each time you flip not the total amount
A = 1/2bh
40 = 1/2 x^2
x^2 = 80
x = 8.9
You have the correct answer. Nice work. If you need to see the steps, then see below
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First we need to find the midpoint of H and I
The x coordinates of the two points are -4 and 2. They add to -4+2 = -2 and then cut that in half to get -1
Do the same for the y coordinates: 2+4 = 6 which cuts in half to get 3
So the midpoint of H and I is (-1,3). The perpendicular bisector will go through this midpoint
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Now we must find the slope of segment HI
H = (-4,2) = (x1,y1)
I = (2,4) = (x2,y2)
m = (y2 - y1)/(x2 - x1)
m = (4 - 2)/(2 - (-4))
m = (4 - 2)/(2 + 4)
m = 2/6
m = 1/3
Flip the fraction to get 1/3 ---> 3/1 = 3
Then flip the sign: +3 ----> -3
So the slope of the perpendicular bisector is -3
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Use m = -3 which is the slope we found
and (x,y) = (-1,3), which is the midpoint found earlier
to get the following
y = mx+b
3 = -3*(-1)+b
3 = 3+b
3-3 = 3+b-3
0 = b
b = 0
So if m = -3 and b = 0, then y = mx+b turns into y = -3x+0 and it simplifies to y = -3x
So that confirms you have the right answer. I've also used GeoGebra to help confirm the answer (see attached)
Let the vertex angle be x.
Base angles in the isosceles triangle are congruent.
Let the base angles be α=34°
Total sum of the inner angles in the triangle is 180°.
We can make equation
2α+x=180° => x=180-2α=180-68=112
The measure of the vertex angle is 112°
Good luck!!!