Answer:
(u+2)(2a+9)
Step-by-step explanation:
2a(u+2)+9(u+2)
Taking (u+2) common
We get
(u+2)(2a+9)
The correct answer is 673
9+4= 13
5 turns into a 6 so it’s 6+1 = 7
3+3 = 9
Answer:
18
Step-by-step explanation:
15 x 2 = 30
30 - 12 = 18
18 girls are in his class
Answer:
y - 7 = 4(x - 35)
Step-by-step explanation:
The fundamental theorem of calculus states that:
= f(x).
So using the fundamental theorem of calculus, you can find that h'(x) = f(x).
The question tells you that f(x) is periodic with a period of 8, so f(x) repeats itself every 8 units.
Using this, you can find that the slope of h(x) at x = 35 is the same as the slope of h(x) at x = 3, which is 4.
The slope of h(x) at x = 35 is 4.
Now I have to find the value of h(x) when x = 35. It is the area under f(x) from 0 to 35.
The area underneath f(x) from 0 to 35 is 7. When x = 35, h(x) = 7.
Now use the point-slope formula to write the equation of the tangent line.
The answer is <u>y - 7 = 4(x - 35)</u>
Answer:
Rolling case achieves greater height than sliding case
Step-by-step explanation:
For sliding ball:
- When balls slides up the ramp the kinetic energy is converted to gravitational potential energy.
- We have frictionless ramp, hence no loss due to friction.So the entire kinetic energy is converted into potential energy.
- The ball slides it only has translational kinetic energy as follows:
ΔK.E = ΔP.E
0.5*m*v^2 = m*g*h
h = 0.5v^2 / g
For rolling ball:
- Its the same as the previous case but only difference is that there are two forms of kinetic energy translational and rotational. Thus the energy balance is:
ΔK.E = ΔP.E
0.5*m*v^2 + 0.5*I*w^2 = m*g*h
- Where I: moment of inertia of spherical ball = 2/5 *m*r^2
w: Angular speed = v / r
0.5*m*v^2 + 0.2*m*v^2 = m*g*h
0.7v^2 = g*h
h = 0.7v^2 / g
- From both results we see that 0.7v^2/g for rolling case is greater than 0.5v^2/g sliding case.
