Answer:
If 12,000 are put at an account with 2.5% compound interest in 15 years your total would be $17,379.58
Answer:
It’s C
Step-by-step explanation:
We are going to rewrite both numbers:
(4.2 × 10 ^ 6) = 4200000
(2.25 × 10 ^ 5) = 225000
Adding we have:
4200000 + 225000 = 4425000
Rewriting in exponential notation we have:
4425000 = 4,425 * 10 ^ 6
Answer:
(4.2 × 10 ^ 6) + (2.25 × 10 ^ 5) is equal to:
4,425 * 10 ^ 6
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
Answer:
ab/3
Step-by-step explanation:
I don't really know how to explain.
Μα†hway
hope this helps!
