All categories

3 years ago

How to round 147.37 to the one?

Mathematics

2 answers:

never [62]3 years ago

4 0

If it's to the ones place it's the digit 7 next to the four (that's what we're rounding)

Then we look to the digit on the left. If it's 5 or higher you round it up a digit. If it's less than 5 you round it done one digit.

so,

147.37 is rounded to:

147

N76 [4]3 years ago

3 0

Answer:

same thing

Step-by-step explanation:

To round 14,737 to the nearest ones place...

The digit in the ones place in your number is the 7. To begin the rounding, look at the digit one place to the right of the 7, or the , which is in the place.

Since the is less than 5, we'll round our number down by

Leaving the 7 in the ones place alone.

Changing all digits to the right of this 7 into zeros.

The result is: 14,737.

So, 14,737 rounded to the ones place is 14,737.

You might be interested in

A company that manufactures toothpaste is studying five different package designs. Assuming that one design is just as likely to

Vesna [10]

Answer:

20%

Step-by-step explanation:

p(outcomes)=#of favourable outcomes/#of possible outcomes

=1/5

=0.2

=20%

7 0

3 years ago

If 20 squirrels can eat a bushel of corn in 10 hours, how many squirrels can eat a bushel of corn in 2 hours?

omeli [17]

So if 20 squirrels can eat a bushel of corn in 10 hours that means that 2 it needs 2 squirrels per hour.

So the answer would be 4 squirrels, hope this helps!

7 0

4 years ago

Read 2 more answers

What is the value of g?<br> g<br> 70

lara [203]

Answer: 70

Step-by-step explanation:

easy

3 0

3 years ago

The design of a digital box camera maximizes the volume while keeping the sum of the dimensions at 6 inches. If the length must

love history [14]

H = x, L = 1.5 x;
L + W + H = 6
x + 1.5 x + W = 6
W = 6 - 2.5 x
Dimensions of the camera in terms of x:
x, 1.5 x, 6 - 2.5 x.
V = L x W x H
V = x * 1.5 x * ( 6 - 2.5 x ) = 9 x² - 3.75 x³
V ` = 18 x - 11.25 x² ( V max is when V` = 0 )
18 x - 11.25 x² = 0
x ( 18 - 11.25 x ) = 0
11.25 x = 18
x = 18 : 11.25
x = 1.6
The dimensions are:
L = 2.4
W = 2.0
H = 1.6

4 0

4 years ago

Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x

Svet_ta [14]

Answer:

$A^{'}$ = {1,3,5,7,9,....}

$B^{'}$ = {1,2,4,5,7,8,10,11,13,14......}

$C^{'}$ = {1,2,3,4,5}

$D^{'}$ = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

$A^{'}$ = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

$A^{'}$ = {1,3,5,7,9,....}

$B^{'}$ = U-B = {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

$B^{'}$ = {1,2,4,5,7,8,10,11,13,14......}

$C^{'}$ = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

$C^{'}$ = {1,2,3,4,5}

$D^{'}$ = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

$D^{'}$ = {10,11,12,13,14,15,......}

8 0

3 years ago