Answer:
The Volume of large cone is 19.545
greater than the smaller cone
Step-by-step explanation:
Given:
Size of the small cone = 3.5 inches
Diameter of the small cone = 3 inches
Size of the large cone = 3.5 inches
Diameter of the small cone = 3 inches
To Find:
How much greater, to the nearest tenth of a cubic inch, is the volume of the larger cone than the volume of the smaller cone = ?
Solution:
Volume of the small cone :
Radius = 
Radius = 
Radius = 1.5 inches
volume of the cone =
substituting the values,
=>
=>
=> 16.485 
Volume of the large cone :
Volume of the large cone :
Radius = 
Radius = 
Radius = 2.25 inches
volume of the cone =
substituting the values,
=>
=>
=>36.06 
Now ,
volume of small cone - volume of large cone
=>36.06 - 16.485
=>19.545 
Answer:
9x2x1 and 6x3x1
Step-by-step explanation:
This question has multiple answers to it. A sandbox of 18 cubic feet with a height of a foot is actually quite simple. If it is confusing I would try to visualize the sandbox. Since volume is b x h x w the first thing you should do is divide 18 by 1. This would be more important if the height was more than one. Now you just have to find two other numbers that can divide 18. 9x2=18 and 6x3=18 so two possible dimensions for the sandbox are 9x2x1 and 6x3x1
Answer:
6:10
Step-by-step explanation:
3:5 is equivalent to 6:10 because you multiply both 3 and 5 by 2 and you get 6:10. every thing else is wrong