Answer:
Yes
Step-by-step explanation:
When graphed, the equation will produce a straight line, making it linear.
Answer:
120.51·cos(377t+4.80°)
Step-by-step explanation:
We can use the identity ...
sin(x) = cos(x -90°)
to transform the second waveform to ...
i₂(t) = 150cos(377t +50°)
Then ...
i(t) = i₁(t) -i₂(t) = 250cos(377t+30°) -150cos(377t+50°)
A suitable calculator finds the difference easily (see attached). It is approximately ...
i(t) = 120.51cos(377t+4.80°)
_____
The graph in the second attachment shows i(t) as calculated directly from the given sine/cosine functions (green) and using the result shown above (purple dotted). The two waveforms are identical.
Answer:
A) x + 0
Step-by-step explanation:
In triangle ABC, the coordinates are: A(1, -1), B(1, -5) and C(4, -5)
In triangle A'B'C', the coordinates are: A(1, -5), B(1, 1) and C(4, 1)
Look at the x-coordinates in both the triangles remains the same because the triangles are reflected over x-axis, therefore, only the y-coordinate changes.
Therefore, the rule for x-coordinates = x + 0
Answer: A) x + 0
Hope this was helpful.
Thank you.
Answer:
It is proportional
Step-by-step explanation:
㏒₂(5x + 3) = 3
2³ = 5x + 3 Cange the equation.
8 = 5x + 3 Multiphy 2 by itself three times.
- 3 - 3 Subtract 3 from each side.
5 = 5x
5 5 Divide it by 5
1 = x Find the answer.