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gavmur [86]
3 years ago
14

How many nober cobenations can you make with two qurters one dime and one nickel

Mathematics
1 answer:
Bezzdna [24]3 years ago
8 0
9 combinations hope it helps
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Pls help!! and explain why the answer is correct !
pochemuha

Step-by-step explanation:

-3(2x-6)+4=-6x+18+4=-6x+22

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3 years ago
I need this ASAP MY TEACHER KEEPS CONTACTING ME PLZ HELP Combine like terms: 9x+8y-4x-2y9x+8y−4x−2y
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Answer:

If the expression is 2y+9x the answer is: 10x+12y

If the expression is 2y-9x the answer is -8x+12y

Step-by-step explanation:

You would combine all your x values:-4,9,9,-4 and that equals 10 then you would add your variable, so your x value is 10x.

You would then combine all your y values: 8,-2,8,-2, and that equals 12, then you would add your variable, so your y value is 12y.

8 0
2 years ago
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Going against the current, a boat takes 6 hours to make a 120-mile trip. When the boat travels with the current on the return tr
Andrew [12]

Answer:

120 miles/6 hours = 20 mph. You need to do the same for the boat going with the current. 120 miles/ 5 hours = 24 mph.

Step-by-step explanation:

5 0
3 years ago
There are 12 inches in 1 foot. Jada is working on improving her vertical jump. She records,
guajiro [1.7K]

Answer:

There are <u>72 inches</u> in 6 feet.

Step-by-step explanation:

Given:

There are 12 inches in 1 foot.

Jada is working on improving her vertical jump.

Currently, her standing reach is 6 feet from the ground.

Now, to find the inches in 6 feet.

Let the inches in 6 feet be x.

As given:

In 1 foot there are 12 inches.

<em>So, 1 foot is equivalent to 12 inches.</em>

<em>Thus, 6 feet is equivalent to </em>x<em />

Now, to find using cross multiplication method:

\frac{1}{12} =\frac{6}{x}

<em>By cross multiplying we get:</em>

x=72

So, the inches in 6 feet = 72.

Therefore, there are 72 inches in 6 feet.

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3 years ago
Solve for x. <br><br> a²x+(a-8)=(a+8)x
Sergio [31]
a^2x+(a-8)=(a+8)x\\\\(a+8)x=a^2x+(a-8)\ \ \ \ |subtract\ a^2x\ from\ both\ sides\\\\(a+8)x-a^2x=a-8\\\\(a+8-a^2)x=a-8\ \ \ \ |divide\ both\ sides\ by\ (a+8-a^2)\\\\\huge\boxed{x=\frac{a-8}{a+8-a^2}}\to\huge\boxed{x=\frac{8-x}{a^2-a-8}}
6 0
3 years ago
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