Question

Please help.............

Answer 1

Answer:

f(n) = 6* (3)^(n-1)

Step-by-step explanation:

We are multiplying by 3 each time

6*3 =18

18*3 = 54

So the common ratio is 3

The first term is 6

The formula for the geometric sequence is

an = a1 r^(n-1)

an = 6* (3)^(n-1)

f(n) = 6* (3)^(n-1)

Answer 2

Answer:

Step-by-step explanation:

The answers to A and B are both 1 when n = 1. Try it.

f(n) = 3^n

f(1) = 3^(1 - 1)

f(1) = 3^0     Anything to the 0 (except 0) = 1  (18.4344423432)^0 = 1

So when n = 1 both A and B go to 1.

I think you will find that C is the correct answer.

f(2) = 6(3^(2 - 1)

f(2) = 6( 3^1)

f(2) = 6*3

f(2) = 18

If you follow the same steps for D you will find the n = 3 won't work

f(3) = 2*(6^(3 - 1))

f(3) = 2*(6^2)

f(3) = 2* 36

f(3) = 72 which is not 54.

Answer C