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Vinil7 [7]
4 years ago
11

Create a program that prints out a list of all the divisors of a number stored in a variable. (If you don’t know what a divisor

is, it is a number that divides evenly into another number. For example, 13 is a divisor of 26 because 26 / 13 has no remainder. If the desired number is 26, your program should print 1, 2, 13, and 26.)
Computers and Technology
1 answer:
UkoKoshka [18]4 years ago
7 0

Answer:

// Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include<iostream>

using namespace std;

int main()

{

// Declare integer variable n which serves as the quotient.

int n;

// Prompt to enter any number

cout<<"Enter any integer number: ";

cin>>n;

// Check for divisors using the iteration below

for(int I = 1; I<= n; I++)

{

// Check if current digit is a valid divisor

if(n%I == 0)

{

// Print all divisors

cout<<I<<" ";

}

}

return 0;

}

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Answer:

int ComputeFibonacci(int N) {

   if(N == 0)

       return 0;

   else if (N == 1)

       return 1;

   else

       return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);

}

Explanation:

Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.

For example,

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*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and  ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.

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