Both are right b/c like sean says you can add zero and itll still be -100 but candice is also right b/c because you can add any # to that -100 but you can also add a negative # to get it back to -100. for example: -100+23= -77 but if you also add a negative 23 it would be right back to -100.
Hahahah yes i would but its a white screen!
The standard error (SE) of the sampling distribution difference between two proportions is given by:

where p is the pooled sample proportion,

<span> is the size of sample 1, and

<span> is the size of sample 2.
</span>

<span>
Given that a</span><span>t one vehicle inspection station, 13 of 52 trucks and 11 of 88 cars failed the emissions test.
</span>

<span>
</span>

<span>
</span>
</span>
Answer + Explanation + Theory
When a number is divided by a number it results in a quotient and a remainder
E.g. 9 / 4 = 2 remainder 1
9 is the dividend
4 is the divisor
2 is the quotient
1 is the remainder
Same way when a polynomial is divided by a linear expression
E.g.
Ax^2 + bx + c / (x-b) = (x+a) + r
Which can be rearranged to
ax^2 + bx + c = (x+a)(x-b) + r
When x = - a or b, only the remainder is left since either (x+a)(x-b) is 0.
If x = - a or b is substituted into the polynomial and the value is 0 then there is no remainder,
This would suggest (x+a) or (x-b) are factors of the polynomial.
Now apply this logic to these questions
1. Let’s assume (x-4) is a factor, this would mean that when x=4 is substituted into the polynomial the answer would be 0.
This is the case, therefore the remainder is 0.
2. Having seen the logic above (applied using the remainder and factor theorem) the linear expression is a factor of the polynomial.