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hodyreva [135]
3 years ago
8

What are all of the real roots of the following polynomial?

Mathematics
1 answer:
olganol [36]3 years ago
7 0

Answer:

The correct answer is A

Step-by-step explanation:

I got it correct on plato .

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Sean says that to add a number to -100 and still have -100 is to add zero.candice says that she can add two numbers to -100 and
elena-s [515]
Both are right b/c like sean says you can add zero and itll still be -100 but candice is also right b/c because you can add any # to that -100 but you can also add a negative # to get it back to -100. for example: -100+23= -77 but if you also add a negative 23 it would be right back to -100.
4 0
4 years ago
Can someone help me with these math problems?
kondor19780726 [428]
Hahahah yes i would but its a white screen!
6 0
3 years ago
Read 2 more answers
Can someone help me with this answer I’m on a test and it’s almost due
Brrunno [24]

16.5 / p = 11 / 18

p = 16.5 × 18 / 11

p = ( 16.5 / 11 ) × 18

p = 1.5 × 18

p = 27

6 0
3 years ago
At one vehicle inspection station, 13 of 52 trucks and 11 of 88 cars failed the emissions test. assuming these vehicles were rep
Leto [7]
The standard error (SE) of the sampling distribution difference between two proportions is given by:

SE=\sqrt{p(1-p)\left(\frac{1}{n_1}+\frac{1}{n_2}\right)}

where p is the pooled sample proportion, n_1<span> is the size of sample 1, and n_2<span> is the size of sample 2.

</span>p= \frac{p_1n_1+p_2n_2}{n_1+n_2}
<span>
Given that a</span><span>t one vehicle inspection station, 13 of 52 trucks and 11 of 88 cars failed the emissions test.

</span>p_1= \frac{13}{52} =0.25 \\  \\ p_2= \frac{11}{88} =0.125 \\  \\ n_1=52 \\  \\ n_2=88 \\  \\ p= \frac{0.25(52)+0.125(88)}{52+88}  \\  \\ = \frac{13+11}{140} = \frac{24}{140} =0.1714
<span>
</span>SE=\sqrt{0.1714(1-0.1714)\left(\frac{1}{52}+\frac{1}{88}\right)} \\  \\ = \sqrt{0.1714(0.8286)(0.0192+0.0114)}  \\  \\ = \sqrt{0.1714(0.8386)(0.0306)} = \sqrt{0.0044}  \\  \\ =0.0663<span>
</span> </span>
5 0
4 years ago
Read 2 more answers
Given p(x) = x4 + x3 - 13x2 - 25x - 12
skad [1K]
Answer + Explanation + Theory

When a number is divided by a number it results in a quotient and a remainder

E.g. 9 / 4 = 2 remainder 1

9 is the dividend
4 is the divisor
2 is the quotient
1 is the remainder

Same way when a polynomial is divided by a linear expression

E.g.

Ax^2 + bx + c / (x-b) = (x+a) + r

Which can be rearranged to

ax^2 + bx + c = (x+a)(x-b) + r

When x = - a or b, only the remainder is left since either (x+a)(x-b) is 0.

If x = - a or b is substituted into the polynomial and the value is 0 then there is no remainder,

This would suggest (x+a) or (x-b) are factors of the polynomial.

Now apply this logic to these questions

1. Let’s assume (x-4) is a factor, this would mean that when x=4 is substituted into the polynomial the answer would be 0.

This is the case, therefore the remainder is 0.

2. Having seen the logic above (applied using the remainder and factor theorem) the linear expression is a factor of the polynomial.
3 0
3 years ago
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