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3 years ago

14

There are 8 and 2 over 3pounds of walnuts in a container, which will be divided equally into containers that hold 1 and 1 over 5

pounds. This would fill ____ and 4 over 18containers

1 answer:

kow [346]3 years ago

6 0

Answer:

7 4/18

Step-by-step explanation:

(8 2/3)/(1 1/5) = (26/3)/(6/5) = (26/3)(5/6) = 130/18 = 7 4/18

7 is the integer that goes in the blank

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What is cos theta when sin theta = sqrt 2/3

Fittoniya [83]

<u>Answer:</u>

Value of cosθ is ±√7/3 .

<u>Step-by-step explanation:</u>

According to the Question , value of :

$\red{\implies sin\theta = \dfrac{\sqrt2}{3}}$

And , we know the identity of sine and cosine as ,

$\boxed{\pink{\sf\implies sin^2\theta + cos^2\theta = 1} }$

<u>Using</u><u> </u><u>,</u><u> </u><u>this</u><u> </u><u>ident</u><u>ity</u><u> </u><u>we</u><u> </u><u>have</u><u> </u><u>;</u><u> </u>

$\implies sin^2\theta + cos^2\theta = 1 \\\\\implies \bigg( \dfrac{\sqrt2}{3}\bigg)^2 + cos^2\theta = 1 \\\\\implies \dfrac{2}{9} + cos^2\theta = 1 \\\\\implies cos^2\theta = 1 - \dfrac{2}{9} \\\\\implies cos^2\theta = \dfrac{9-2}{9} \\\\\implies cos\theta = \sqrt{\dfrac{7}{9}} \\\\\underline{\boxed{\blue{\bf \implies cos\theta = \pm \dfrac{\sqrt 7 }{3}}}}$

Now , here since θ is in 2nd quadrant and in 2nd quadrant cos is negative . Hence ,the value of cos will be :

$\boxed{\orange{\bf \implies cos\theta =-\dfrac{\sqrt7}{3}}}$

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3 years ago

A national organization sets out to investigate the change in prevalence of HIV since the last census in 2010. A total of 4,706

nikitadnepr [17]

Answer:

As can be seen, there has been a rise in the proportion of the population with HIV positive, from 7.5% to 9.94%.

Step-by-step explanation:

Given that a national organization sets out to investigate the change in prevalence of HIV since the last census in 2010, ya total of 4,706 participants were interviewed and a total of 468 responses were confirmed to be HIV positive, assuming that the data from the census indicated that the prevalence of HIV in the particular population was 7.5%, to determine if the proportion of the prevalence of HIV has changed (is equal to 7.5%) the following calculation should be performed:

4706 = 100

468 = X

468 x 100/4706 = X

46,800 / 4,706 = X

9.94 = X

Therefore, as can be seen, there has been a rise in the proportion of the population with HIV positive, from 7.5% to 9.94%.

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3 years ago

What is the net force on a 1,000 kg object accelerating at 3 m/s2 ?

anzhelika [568]

3 $3 \leq m+1.4$

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3 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

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4 years ago

Reflect each point in the x-axis and y-axis

Vilka [71]

Step-by-step explanation:

1. x: (-12, -13) y: (12, 13)

2. x: (4 ,9) y: (-4, -9)

3. x: (-10, 8) y: (10, -8)

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3 years ago

Read 2 more answers