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Westkost [7]
3 years ago
12

What is the probability of getting heads and a b, c, and d

Mathematics
1 answer:
sp2606 [1]3 years ago
4 0
I mean probably of getting head is a half if that's what u mean but what is a,b,c,d
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What is the area of a circle with a radius of 5 units?
baherus [9]
A=pi(c/2)^4=pi^2/c^216=(5pi)^2/8=25pi^2/8
5 0
3 years ago
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11. In AWTY, if mZW is five less than twice mZY and mZX is 21 more than m_Y find the measure
wolverine [178]

9514 1404 393

Answer:

  angles (W, X, Y) = (77°, 62°, 41°)

Step-by-step explanation:

<u>Given</u>:

  ΔWZY

  ∠W = 2(∠Y) -5°

  ∠X = ∠Y +21°

<u>Find</u>:

  ∠X, ∠Y, ∠W

<u>Solution</u>:

Using angle measures in degrees, we have ...

  ∠X + ∠Y + ∠Z = 180

  (∠Y +21) +∠Y + (2(∠Y) -5) = 180

  4(∠Y) +16 = 180 . . . . . simplify

  ∠Y +4 = 45 . . . . . . . . . divide by 4

  ∠Y = 41 . . . . . . . . . . . . subtract 4

  ∠W = 2(41) -5 = 77

  ∠X = 41 +21 = 62

The angle measures of angles (W, X, Y) are (77°, 62°, 41°), respectively.

7 0
3 years ago
What is 37.726 rounded to the nearest tenth
pochemuha
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).

37.7\fbox26\approx\huge\boxed{37.7}
7 0
3 years ago
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Riley tried the following homework question:
blondinia [14]

Answer:

her balance aka ADB would be 372.08

4 0
2 years ago
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
3 years ago
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