Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
1300 = 2 × 2 × 5 × 5 × 13, <span>36 = 2 × 2 × 3 × 3</span>
Use the distance formula and simply substitute in the corresponding orders pairs.
Distance = √(x2 - x1)² + (y2 - y1)²
Distance = √(4 - (-6))² + (3 - (-1))²
Distance = √(4 + 6)² + (3 + 1)²
Distance = √(10)² + (4)²
Distance = √100 + 16
Distance = √116
Distance = 10.7703296143
Round to the nearest hundredth!
Distance ≈ 10.77
