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kirill115 [55]
4 years ago
5

A bag contains 10 marbles: 3 are green, 2 are red, and 5 are blue. Jose chooses a marble at random, and without putting it back,

chooses another one at random. What is the probability that the first marble is red and the second is blue? Write your answer as a fraction in simplest form.
Mathematics
1 answer:
Ludmilka [50]4 years ago
6 0
We know that
g=3
r=2
b=5
total marbies=g+r+b------> 3+2+5----> 10

a) <span>probability that the first marble is red
P(red)=r/total marbies------------> 2/10-----> 1/5

b) </span><span>probability that the second marble is blue
in this case total marbles-------> 9
P(blue)=b/total marbles----------> 5/9

c) </span><span>the probability that the first marble is red and the second is blue
(1/5)*(5/9)=1/9

the answer is
1/9</span>
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3 years ago
If a security pays $55 in one year and $133 in three years, its present value is $150 if the interest rate is
Evgesh-ka [11]

Answer:

10%

Step-by-step explanation:

What we will do is apply the present value formula that would be as follows:

PV = P1 / (1 + R) + P2 / (1 + R) ^ 2 + ... + Pn / (1 + R) ^ n

Where VP is the present value, P would be the payment in each corresponding year and R what we are looking for, the interest rate.

Replacing we have the following values:

150 = 55 / (1 + R) + 133 / (1 + R) ³

We have a cubic equation that here is very complex to answer so we are going to use the symbolab tool.

Next we can see how it calculates the value of R step by step.

https://es.symbolab.com/solver/step-by-step/150%20%3D%2055%20%2F%20%5Cleft(1%20%2B%20R%5Cright)%20%2B%20133%20%2F%20%5Cleft(1%20%2B%20R%5Cright)%20%C2%B3

The result is that R equals approximately 0.09976, therefore the interest rate is 9.976%, or rounding 10%

3 0
3 years ago
A 57-inch television screen has an aspect ratio of 4:3. Find the scale factor (x), find the length and width, and calculate the
natulia [17]

tv-sets are rated by the screen size and the screen size comes from the length of its diagonal.

so a 57" TV has a 57" diagonal.

Check the picture below.

\bf \stackrel{length}{4\left( \cfrac{57}{5} \right)}\implies \cfrac{228}{5}\implies 45\frac{3}{5}~\hfill \stackrel{width}{3\left( \cfrac{57}{5} \right)}\implies \cfrac{171}{5}\implies 34\frac{1}{5} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{Area}{\cfrac{228}{5}\cdot \cfrac{171}{5}}\implies \cfrac{38988}{25}\implies 1559\frac{13}{25}

3 0
4 years ago
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