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2 years ago

**DUE AT 2:15 P.M, NEED ANSWER NOW

Mathematics

1 answer:

Natalka [10]2 years ago

8 0

Answer:

You should guess

Step-by-step explanation:

If you have good luck you will get it right

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In circle P with mNRQ = 60°, find the angle measure of minor arc NQ

Galina-37 [17]

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)$

Multiply by 2 on both sides.

$$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)$

$$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)$

Substitute m∠NRQ = 60°.

$$\Rightarrow 2\times 60^\circ=m(ar NQ)$

$$\Rightarrow 120^\circ=m(ar NQ)$

The measure of minor arc NQ is 120°.

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3 years ago

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Pachacha [2.7K]

Answer:

Option A. <A and <B are complementary angles

Option D. $Sin(C)=Cos(90\°-C)$

Step-by-step explanation:

we know that

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then

------> by complementary angles

and

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$Cos(C)=Sin(A)$

Remember that

$A=90\°-C$

$Sin(C)=Cos(90\°-C)$

$Cos(C)=Sin(90\°-C)$

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