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Elodia [21]
3 years ago
7

A box is sitting on the floor. The box was then pulled with a force, Ft. The box did not move. The free-body diagram of the box

is shown.
Which describes the motion of the box based on the resulting free-body diagram?

A. It is moving up with a net force of 20 N.

B. It is moving to the right with a net force of 10 N.

C. It is in dynamic equilibrium with a net force of 0 N.

D. It is in static equilibrium with a net force of 0 N.
Mathematics
2 answers:
WINSTONCH [101]3 years ago
5 0

Answer:

A

Step-by-step explanation:

-BARSIC- [3]3 years ago
4 0

Answer:

It is in static equilibrium

Explanation:

edge 2021

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zubka84 [21]

Answer:

The answer is B

Step-by-step explanation:

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2 years ago
4. How fast was a driver going if the car left skid marks that were 32 feet long on dry concrete? (The coefficient of friction i
Monica [59]

Answer:

v_{o} \approx 31.247\,mph

Step-by-step explanation:

The deceleration experimented by the car is the product of kinetic coefficient of friction and gravitational constant:

a = \mu_{k}\cdot g

a = (1.02)\cdot \left(32.174\,\frac{ft}{s^{2}} \right)

a = 32.817\,\frac{ft}{s^{2}}

The initial speed is computed from the following kinematic expression:

v^{2} = v_{o}^{2} - 2\cdot a \cdot \Delta s

v_{o} = \sqrt{v^{2}+2\cdot a\cdot \Delta s}

v_{o} = \sqrt{\left(0\,\frac{ft}{s} \right)^{2}+2\cdot \left(32.817\,\frac{ft}{s^{2}} \right)\cdot (32\,ft)}

v_{o}\approx 45.829\,\frac{ft}{s}

v_{o} \approx 31.247\,mph

8 0
3 years ago
Which segment is parallel to AD
Alex73 [517]

Answer:

BC

Parallel: Two sides or lines are parallel if they are lines that are always the same distance from each other and will never intersect or touch      

8 0
3 years ago
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I need algebra help.....
Lubov Fominskaja [6]

Answer:

y=4(3)^x

Step-by-step explanation:

From the table given in the question,

x            y              Difference                  Ratio

1            12                     -                             -

2           36              36-12 = 24              \frac{36}{12}=3

3          108            108-36 = 72             \frac{108}{36}=3

4          324            324-108 = 216        \frac{324}{108}=3

5          972            972-324 = 648      \frac{648}{216}=3

There is a common ratio of 3 in each successive term.

Therefore, data given in the table will represent an exponential function.

y=a(b)^x

For a point (1, 12),

12=a(b)^1

ab=12 ------(1)

For another point of the table (2,36),

36=a(b)^2

ab^2=36 --------(2)

Equation (2) divided by equation (1)

\frac{ab^2}{ab}=\frac{36}{12}

b=3

From equation (1),

3a=12

a=4

Therefore, exponential function will be,

y=4(3)^x

7 0
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There are two sets of traffic lights outside Eric's house. One day, he times how often they change. Set A turns green every 60 s
Otrada [13]

Answer:

12:07pm

Step-by-step explanation:

first common multiple of 60 and 70 is 420

420 s = 7 mins

3 0
3 years ago
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