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borishaifa [10]
4 years ago
11

Need help solve this please Math question

Mathematics
1 answer:
Masja [62]4 years ago
6 0

Answer:

Answer is B

Step-by-step explanation:

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aleksandrvk [35]
So this is a lot of work but ghe answers are (fix)
4 0
3 years ago
Read 2 more answers
7). Tim has 9 chocolate chip cookies and 18 peanut butter cookies. He
Naily [24]

Answer:

2 groups

Step-by-step explanation:

  1. 18 ÷ 9 = 2 groups

I hope this helps!

4 0
3 years ago
Can u help this helpless 9th grader ?
nexus9112 [7]

Answer:

y = 4x + 32

Step-by-step explanation:

Given: Temperature at sunrise = 32°F

y is the temperature after x hours of sunrise

Temperature change is 4°F/hour.

The equation of a line in slope intercept form is given by

y = mx +c

where m is the slope, which is the change in value of y to the value of x

and c is the value of y at x = 0

At sunrise, x =0 and y =32

∴ c = 32

Also we see that the change in temperature to that of time is 4/1 = 4

∴ m = 4

Substituting the values of m and c in the equation of line, we have

y = 4x +32


7 0
4 years ago
Read 2 more answers
Which equation shows that the Pythagorean identity is true for 0 = 180 degrees? select the equation that is in the form sin^2 0+
elixir [45]

The equation in the form of the given expression is (0)² + (1)² = 1

<h3>Trigonometry identity</h3>

According to some of the trigonometry identity

sin 0 = 0

cos 0 1

Given the expression below

sin^2 0+cos^2 0=1

This can also be expressed as:

(sin0)² + (cos0)² = 1

Substitute

(0)² + (1)² = 1

Hence the equation in the form of the given expression is (0)² + (1)² = 1

Learn more on trig identity here: brainly.com/question/20094605

#SPJ1

8 0
2 years ago
Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

\sigma=\sqrt{\frac{p*(1-p)}{n} }

If n=1139 and p =0.96, the standard deviation is:

\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836

The minimum and maximum usual values are:

\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n

\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62

5 0
3 years ago
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