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crimeas [40]
4 years ago
5

PLEASE HELP ME ASAP PLEASE FAST!!!!!!!!!!!!! PLEASE HELP

Mathematics
1 answer:
Elanso [62]4 years ago
7 0

Answer:

Number the boxes on the left 1–8 from top to bottom. Then their correct order on the right is 3, 7, 8, 4, 6, 5, 2, 1

Step-by-step explanation:

Trade the cube root for a 1/3 power:

(875x^5y^9)^(1/3)

Distribute the 1/3 power:

(125·7)^(1/3)·x^(5/3)·y^(9/3)

Further distribute the powers, rewrite the improper fractions:

125^(1/3)·7^(1/3)·x^(3/3+2/3)·y^3

Write 125 as a cube and simplify 3/3:

(5^3)^(1/3)·7^(1/3)·x^(1+2/3)·y^3

Simplify the cube root of a cube and the x term:

5·7^(1/3)·x·x^(2/3)·y^3

Group the terms with fractional exponents:

5·x·y^3·(7^(1/3)·x^(2/3))

Factor out the 1/3 exponent:

5xy^3·(7x^2)^(1/3)

Trade the 1/3 exponent for a cube root symbol:

5xy^3·∛(7x^2)

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Step-by-step explanation:

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